# What is the domain and range of #g(x)=2x^2-x+1#?

##### 1 Answer

Feb 10, 2016

Domain:

Range:

#### Explanation:

So Domain

and we can determine its minimum value by re-writing its expression in vertex form:

#2x^2-x+1#

#=2(x^2-1/2xcolor(blue)(+(1/4)^2))+1 color(blue)(-1/8)#

#=2(x-1/4)^2+7/8#

#color(white)("XXXXXXXXX")# with vertex at#(1/4,7/8)#

So the Range

graph{2x^2-x+1 [-2.237, 3.24, -0.268, 2.47]}